Question:
Two identical ice skaters are holding onto opposite ends of a very long spring with
a spring constant of 650 N/m. While spinning in a circle, the skaters frequency of
revolution is measured to be 0.85 Hz. Calculate the mass of the skaters.
Answer:
f = (1/2 π)(√ k/m)
0.85 = (1/2 π)(√ 650/m)
m = 22.8 kg
22.8 x 2 = 45.6 kg (the mass need to double since circular motion is the resultant
of two perpendicular SHM with the same frequency and amplitude and phase
difference of π/2.)
Monday, November 26, 2012
Tuesday, November 20, 2012
Physics Question & Answer Key
Question:
A car traveling at constant speed negotiates a frictionless banked curved. Calculate the speed of the car when the road is banked at 20 degrees and the radius of its path is 50 meters.
Answer:
When the road is banked at angle 20 degrees,
The normal force is inclined at angle 20 degrees to the vertical
Its horizontal component
mg sin 20 = centripetal force = mv^2/r
Its vertical Component balances the weight
mg cos 20 = mg
Dividing the first by the second equation
tan 20 = v^2/(rg)
v^2 / 50 = (9.8)(tan 20)
v = 13.35 m/s
A car traveling at constant speed negotiates a frictionless banked curved. Calculate the speed of the car when the road is banked at 20 degrees and the radius of its path is 50 meters.
Answer:
When the road is banked at angle 20 degrees,
The normal force is inclined at angle 20 degrees to the vertical
Its horizontal component
mg sin 20 = centripetal force = mv^2/r
Its vertical Component balances the weight
mg cos 20 = mg
Dividing the first by the second equation
tan 20 = v^2/(rg)
v^2 / 50 = (9.8)(tan 20)
v = 13.35 m/s
Labels:
PQW
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