Showing posts with label MQW. Show all posts
Showing posts with label MQW. Show all posts
Sunday, May 27, 2012
Math Question of the week (5)
The originator of a chain letter writes 5
letters instructing each recipient to write 5 similar letters to additional
people. Then these people each
send 5 similar letters to other people.
Determine the number of people who should receive letters if the chain
continues unbroken for 12 steps.
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MQW
Monday, April 9, 2012
Answer Key for Math question of the week (4)
a. d = 3
b. 152 = 2 + (n −1)(3)
un = a + n − d
u101 = 2 +100—3
u101 = 302
b. 152 = 2 + (n −1)(3)
150 = (n −1)(3),
50 = n −1,
152 = −1+ 3n
n = 51
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MQW
Sunday, March 11, 2012
Math Question of the week (4)
a. Find U101
b. Find the value of n so that Un = 152.

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MQW
Answer Key for Math question of the week (3)
a. 6C4 (0.4)^4 (0.6)^2 = 0.13824
b. (0.6)(0.6)(0.4) = 0.144
b. (0.6)(0.6)(0.4) = 0.144
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MQW
Wednesday, January 25, 2012
Math question of the week (3)
When John throws a stone at a target, the probability that he hits the target is 0.4 He throws a stone 6 times.
(a) Find the probability that he hits the target exactly 4 times.
(b) Find the probability that he hits the target for the first time on his third throw.
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MQW
Sunday, January 15, 2012
Answer key for Math question (2)
a) 7C4 [ (0.9)^4 * (1 - 0.9)^(7 - 4) ]
= 7!/(4!*3!) [(0.9)^4 * (0.1)^3]
= 35(0.0006561)
=0.023
b) 7C4 [p^4 * (1 - p)^3]
= 35p^4(1 - 3p + 3p^2 - p^3)
= 35p^4 - 105p^5 + 105p^6 - 35p^7
c) 0.15 = 35p^4 - 105p^5 + 105p^6 - 35p^7
p = 0.356 or
p = 0.770= 7!/(4!*3!) [(0.9)^4 * (0.1)^3]
= 35(0.0006561)
=0.023
b) 7C4 [p^4 * (1 - p)^3]
= 35p^4(1 - 3p + 3p^2 - p^3)
= 35p^4 - 105p^5 + 105p^6 - 35p^7
c) 0.15 = 35p^4 - 105p^5 + 105p^6 - 35p^7
p = 0.356 or
Labels:
MQW
Wednesday, January 4, 2012
Math question of the week (2)
Evan likes to play two games of chance, A and B.
For game A, the probability that Evan wins is 0.9. He plays game A seven times.
(a) Find the probability that he wins exactly four games.
For game B, the probability that Evan wins is p . He plays game B seven times.
(b) Write down an expression, in terms of p , for the probability that he wins exactly
four games.
(c) Hence, find the values of p such that the probability that he wins exactly four
games is 0.15.
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MQW
Tuesday, December 27, 2011
Answer key for math question (1)
(a)
(i) sin1400 = p
(ii) cos700 = −q
(b)
Using sin2θ + cos2θ =1
cos1400 = ±√1− p2
cos1400 = − √1− p2
(c)
tan140 0 = sin1400/ cos1400
= -p / (√1− p2)
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MQW
Friday, December 23, 2011
Math question of the week (1)
Let p=sin400 and q=cos1100. Give your answers to the following in terms of p and/or q
(a) Write down an expression for
1. sin1400
2. cos1100
(b) Find an expression for cos1400.
(c) Find an expression for tan1400.
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MQW
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