Wednesday, March 13, 2013

Physics Question & Answer Key

A 5.00 x 10^ -2 kg mass with a charge of .75μC is hung by a thin insulated thread. A charge of -0.9μC is held .15m directly to the right so that the thread makes an angle Θ with the vertical. What is the angle Θ and the tension in the string?


Force between charges:
F = [(9e9)(0.75e-6)(0.9e-6)] / (0.15²) 
   = 0.27 N

Gravitational force:
mg = 5e-2 x 9.8 
      = 0.49 N

From a force vector diagram:
0.49N vertically down & 0.27N horizontal - -  combining to form θ from vertical) 

tan θ = 0.27 / 0.49 
θ = 28.9º

sin θ = 0.27 / T 
T =0.27 / (sin28.9) 
   = 0.56 N

2 comments:

  1. where did you get the 9 and 6

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    Replies

    1. Do you mean k and μ?

      Fe = kq1q2 / r^2

      k (coulomb's constant) = 9 x 10^9

      μ = 10^-6

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