When two organ pipes open at both ends are sounded at their first harmonic, 4 beats/second are heard. One pipe is 1000 mm long. Calculate the length of the other pipe.
Answer:
V = 343 m/s
L1 = 1000 mm = 1
m
fbeat = ½f1 – f2½
4 = (343 / 2) – (343 / l2)
λ2 = 2.048
λ2 = 2L2
2.048 = 2 L2
L2 = 1.024 m = 1024 mm
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