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Tuesday, December 27, 2011
Answer key for math question (1)
(a)
(i) sin140
0
=
p
(ii) cos70
0
= −
q
(b)
Using sin
2
θ
+ cos
2
θ
=1
cos140
0
= ±
√
1−
p
2
cos140
0
= −
√
1−
p
2
(c)
tan140
0
= sin140
0
/ cos140
0
= -p / (
√
1−
p
2
)
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