Answer Key for Physics Question of The Week (4)

F = qvB = mv² / r

F = (1.6 x 10^-19)(2 x 10⁷)(0.1)

   = 0.32 x 10^-12

r = [(1.67 x 10^-27)(2 x 10⁷)²] / 0.32 x 10^-12

   = 2.09 m